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Generating Sequence Terms

Updated August 2025

Generating terms of a sequence is a foundational skill for university admission tests. This guide covers term-to-term and position-to-term rules, explaining how to use recursive notation and nnth term formulas to find specific values or determine the exact position of a term within a numerical progression.

Core concept

A sequence is a list of numerical terms generated by a specific rule. A term-to-term rule defines a term based on the preceding one (recursion), whereas a position-to-term rule (the nnth term) defines a term based directly on its index nn.

A sequence is a list of terms together with a rule for generating them. In mathematics for university admission, you are expected to handle two primary types of rules: term-to-term rules and position-to-term rules. Understanding how to navigate between these is key to identifying specific values in a progression or determining if a given number is a member of a set.

Term-to-term Rules

A term-to-term rule specifies how to calculate the next term in a sequence based on the current term. These rules require a starting value, usually denoted as t1t_1. For example, a sequence starting with 3 and using a term-to-term rule of adding 4 would be 3, 7, 11, 15, 19, and so on.

Formal notation often uses tnt_n for the nnth term and tn+1t_{n+1} for the following term. A rule such as t1=7t_1 = 7 and tn+1=tn2t_{n+1} = t_n - 2 generates the sequence 7, 5, 3, 1, -1. This is also known as a recursive definition.

Worked Example: Using a Term-to-term Rule

Find the next four terms in the sequence defined by t1=3t_1 = 3 and tn+1=2tn1t_{n+1} = 2t_n - 1.

  1. For n=1n = 1: t2=(2×t1)1=(2×3)1=5t_2 = (2 \times t_1) - 1 = (2 \times 3) - 1 = 5.
  2. For n=2n = 2: t3=(2×t2)1=(2×5)1=9t_3 = (2 \times t_2) - 1 = (2 \times 5) - 1 = 9.
  3. For n=3n = 3: t4=(2×t3)1=(2×9)1=17t_4 = (2 \times t_3) - 1 = (2 \times 9) - 1 = 17.
  4. For n=4n = 4: t5=(2×t4)1=(2×17)1=33t_5 = (2 \times t_4) - 1 = (2 \times 17) - 1 = 33.

The resulting terms are 5, 9, 17, and 33.

Position-to-term Rules

A position-to-term rule, often referred to as the nnth term rule, allows you to calculate the value of a term based solely on its position nn in the list. This is highly efficient for finding terms far along in a sequence without calculating all intermediate values.

For example, if the rule is 2n12n - 1:

  1. The 3rd term (n=3n = 3) is 2×31=52 \times 3 - 1 = 5.
  2. The 8th term (n=8n = 8) is 2×81=152 \times 8 - 1 = 15.

Worked Example: Finding Terms from an nnth Term Rule

Find the 4th and 10th terms for the sequence whose nnth term rule is 2n+32n + 3.

  1. To find the 4th term, substitute n=4n = 4: (2×4)+3=11(2 \times 4) + 3 = 11.
  2. To find the 10th term, substitute n=10n = 10: (2×10)+3=23(2 \times 10) + 3 = 23.

Checking Membership and Position

Exam questions often require you to determine if a specific value belongs to a sequence or to find the position index nn for a given value. This typically involves solving an algebraic equation.

Worked Example: Deciding if a Number is in a Sequence

Is 272 in the sequence 2, 6, 10, 14, ...? Explain your answer.

The first term is 2 and the term-to-term rule is adding 4. If a term is in this sequence, subtracting the first term (2) must result in a multiple of the common difference (4).

2722=270272 - 2 = 270.

Since 270 is not a multiple of 4 (270÷4=67.5270 \div 4 = 67.5), 272 is not a term in this sequence. This can also be seen by finding the nnth term rule, 4n24n - 2, and setting it equal to 272, which yields n=68.5n = 68.5, which is not an integer.

Worked Example: Finding the Position of a Term

In the sequence n2+2nn^2 + 2n, which term is 35?

To find the position, set the nnth term rule equal to 35 and solve for nn:

n2+2n=35n^2 + 2n = 35 n2+2n35=0n^2 + 2n - 35 = 0 (n+7)(n5)=0(n + 7)(n - 5) = 0

This gives n=7n = -7 or n=5n = 5. Since the position nn must be a positive integer, we discard the negative root. Therefore, 35 is the 5th term of the sequence.

Key takeaways

  • A term-to-term rule requires both a starting value t1t_1 and a relationship between tn+1t_{n+1} and tnt_n.
  • The position of a term, nn, must always be a positive integer (1, 2, 3...).
  • Position-to-term rules (the nnth term) are the most efficient way to find values far into a sequence.
  • To find which term equals a certain value, set the nnth term expression equal to that value and solve for nn.
  • In quadratic sequences, always discard negative solutions for nn as they are physically impossible in the context of a list.
Tips

When faced with a large number and asked for its position, always look for a position-to-term rule. Iterating a term-to-term rule manually is error-prone and time-consuming in an exam.

Cautions

Be careful with the first term. If a rule is 2n+12n + 1, the first term is when n=1n=1, not n=0n=0. Miscounting the starting index is a frequent source of errors in sequence problems.

Insight

Term-to-term rules are the basis for recurrence relations in computer science and advanced calculus. While they are intuitive for building a list, converting them to position-to-term rules is a powerful technique for analysing long-term behaviour.

Worked Examples

Example 1
Evaluate

327+21+324+18+321+15++39+3\frac{3}{\sqrt{27}+\sqrt{21}} + \frac{3}{\sqrt{24}+\sqrt{18}} + \frac{3}{\sqrt{21}+\sqrt{15}} + \dots + \frac{3}{\sqrt{9}+\sqrt{3}}
A:322\frac{3\sqrt{2}}{2}
B:323\sqrt{2}
C:332\frac{3\sqrt{3}}{2}
D:3\sqrt{3}
E:1+21+\sqrt{2}
F:3(1+2)3(1+\sqrt{2})
G:33(1+22)\frac{\sqrt{3}}{3} \left(1+\frac{\sqrt{2}}{2}\right)
H:3(1+22)\sqrt{3} \left(1+\frac{\sqrt{2}}{2}\right)

Practice Questions

Practice Question 1
The function ff is defined on the positive integers as follows:
f(1)=5f(1) = 5, and for n1n \ge 1:
f(n+1)=3f(n)+1f(n + 1) = 3f(n) + 1 if f(n)f(n) is odd
f(n+1)=12f(n)f(n + 1) = \frac{1}{2}f(n) if f(n)f(n) is even

The function
gg is defined on the positive integers as follows:
g(1)=3g(1) = 3, and for n1n \ge 1:
g(n+1)=g(n)+5g(n+1) = g(n) + 5 if g(n)g(n) is odd
g(n+1)=12g(n)g(n+1) = \frac{1}{2}g(n) if g(n)g(n) is even

What is the value of
f(1000)g(1000)f(1000) – g(1000)?
A:-6
B:-5
C:1
D:2
E:4
F:8

Frequently asked questions

What is the difference between tnt_n and nn?

nn represents the position or index of the term in the sequence (e.g., 1st, 2nd, 3rd), while tnt_n represents the actual numerical value at that specific position.

Can a sequence have a fractional position?

No. By definition, a sequence is an ordered list where each term corresponds to a discrete position nn. Therefore, nn must always be a positive integer (n{1,2,3,...}n \in \{1, 2, 3, ...\}).

Is a recursive rule the same as a term-to-term rule?

Yes. In both cases, the value of the next term is defined based on the value of one or more previous terms.

How do I check if a very large number is in an arithmetic sequence?

Find the nnth term rule, set it equal to the large number, and solve for nn. If nn is a positive integer, the number is in the sequence; if nn is a fraction or decimal, it is not.

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