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Direct and Inverse Proportion for the TMUA

Updated August 2025

Understand how to represent and solve relationships where variables change at a constant ratio or in opposite directions. This topic is essential for the TMUA as it requires setting up equations with proportionality constants and interpreting their corresponding graphs. You will learn to handle linear, power, and inverse relationships accurately.

Core concept

Variables xx and yy are in direct proportion if y=kxy = kx for a constant kk, resulting in a straight-line graph through the origin. They are in inverse proportion if y=kxy = \frac{k}{x}, meaning yy increases as xx decreases.

Direct Proportion

Direct proportion occurs when one variable increases in proportion to the increase in another. For instance, if one chocolate bar costs £6£6, then xx bars will cost £6x£6x. In this case, the number of bars and the total price are in direct proportion because there is no reduction for bulk buying.

In general, if yy is directly proportional to xx, we write the relationship as yxy \propto x or as the equation y=kxy = kx, where kk is a non-zero constant known as the constant of proportionality. You may use any letter for the constant, though kk is standard.

Graphs of Direct Proportion

If a graph is plotted of yy against xx and they are in direct proportion, the graph must be a straight line that passes through the origin (0,0)(0, 0). If the line does not pass through the origin, the variables are not in direct proportion.

Example: Identifying Direct Proportion Graphically

Consider the diagram below showing a graph of yy against xx. Is yy directly proportional to xx?

img-15.jpeg

Method 1: By inspection, the graph is a straight line, but it does not pass through the origin. Therefore, yy is not directly proportional to xx.

Method 2: Using the equation y=kxy = kx. From the graph, when x=4x = 4, y=18y = 18. Substituting these into the formula gives 18=4k18 = 4k, so k=4.5k = 4.5. However, if we check another point, such as x=6,y=24x = 6, y = 24, we find that 246×4.524 \neq 6 \times 4.5. Since kk is not constant, the relationship is not direct proportion.

Example: Solving Direct Proportion Problems

On days when the temperature is above 20C20^{\circ}C, the number of ice creams sold in a shop, nn, is proportional to (t15)(t - 15), where tt is the temperature in C^{\circ}C. When the temperature is 20C20^{\circ}C, the shop sells 30 ice creams. How many will it sell when the temperature is 28C28^{\circ}C?

  1. Set up the equation: n=k(t15)n = k(t - 15).
  2. Find kk: Substitute t=20t = 20 and n=30n = 30. This gives 30=k(2015)30 = k(20 - 15), so 30=5k30 = 5k and k=6k = 6.
  3. Solve for the new value: Substitute t=28t = 28 and k=6k = 6 into the equation. n=6(2815)=6(13)=78n = 6(28 - 15) = 6(13) = 78 ice creams.

Inverse Proportion

If two variables are in inverse proportion, one variable increases as the other decreases. For example, the thickness of ice on a pond might be inversely proportional to the air temperature: as the temperature drops, the ice thickness increases.

We say xx is inversely proportional to yy is equivalent to xx being proportional to 1y\frac{1}{y}. This is written as x1yx \propto \frac{1}{y} or x=kyx = \frac{k}{y}.

Graphs of Inverse Proportion

A graph of yy against xx for an inverse proportion relationship takes the form of a reciprocal curve, as shown below:

img-14.jpeg

Example: Verifying Inverse Proportion

Is it reasonable to say yy is inversely proportional to xx in the following graph?

img-16.jpeg

If y=kxy = \frac{k}{x}, then xyxy must equal a constant kk. We check several points:

  • When x=1,y=12    k=12x = 1, y = 12 \implies k = 12
  • When x=2,y=6    k=12x = 2, y = 6 \implies k = 12
  • When x=3,y=4    k=12x = 3, y = 4 \implies k = 12
  • When x=12,y=1    k=12x = 12, y = 1 \implies k = 12 Since xyxy is consistently 12, it is reasonable to assume y1xy \propto \frac{1}{x}.

Example: Solving Inverse Proportion Problems

The number of pairs of gloves sold, nn, is inversely proportional to the temperature tt. When t=5t = 5, n=15n = 15. Find nn when t=3t = 3.

  1. Set up the equation: n=ktn = \frac{k}{t}.
  2. Find kk: 15=k5    k=7515 = \frac{k}{5} \implies k = 75.
  3. Solve: When t=3t = 3, n=753=25n = \frac{75}{3} = 25 pairs of gloves.

Proportion with Powers

Proportionality can also involve powers of variables, such as yx2y \propto x^2 or yxy \propto \sqrt{x}. The general form is y=kxny = kx^n for integer or fractional values of nn.

Example: Proportionality to a Square

The number of water bottles sold, nn, is proportional to the square of the temperature tt. At 12C12^{\circ}C, 72 bottles are sold. How many are sold at 24C24^{\circ}C?

  1. Set up the equation: n=kt2n = kt^2.
  2. Find kk: 72=k×122    72=144k    k=0.572 = k \times 12^2 \implies 72 = 144k \implies k = 0.5.
  3. Solve: When t=24t = 24, n=0.5×242=0.5×576=288n = 0.5 \times 24^2 = 0.5 \times 576 = 288 bottles.

Key takeaways

  • Direct proportion yxy \propto x implies y=kxy = kx and a straight line graph passing through (0,0)(0, 0).
  • Inverse proportion y1xy \propto \frac{1}{x} implies y=kxy = \frac{k}{x} and a reciprocal curve graph.
  • Always calculate the constant of proportionality kk using a known pair of values before solving for other variables.
  • Proportionality can involve any power of xx: if yxny \propto x^n, then y=kxny = kx^n.
  • A graph that is a straight line but does not pass through the origin is not an example of direct proportion.
Tips

When given a table of values and asked if the relationship is inverse, quickly multiply xx and yy for each pair. If the product xyxy is constant, it is inverse proportion. If asked about direct proportion, divide yy by xx; if the quotient is constant, it is direct.

Cautions

Many students mistake any straight line for direct proportion. Remember: if it does not pass through (0,0)(0, 0), it is not direct proportion. Also, ensure you apply the power to the variable before multiplying by kk (e.g., in y=kx2y=kx^2, square xx first).

Insight

The relationship x1yx \propto \frac{1}{y} is mathematically identical to y1xy \propto \frac{1}{x}. This symmetry is why the constant kk can be found by simply multiplying the two variables together: k=xyk = xy.

Worked Examples

Example 1
The total power PP radiated by a star is given by:
P=kR2T4P = kR^2T^4
where
RR is the radius of the star, TT is its surface temperature and kk is a constant.
The power currently radiated by the Sun is
4.0×10264.0 \times 10^{26} W. Towards the end of the Sun's life its radius will increase by a factor of a hundred and its surface temperature will decrease by a factor of two.
What will be the power radiated by the Sun when these changes have occurred?
A:2.5×10272.5 \times 10^{27} W
B:1.0×10281.0 \times 10^{28} W
C:2.0×10282.0 \times 10^{28} W
D:2.5×10292.5 \times 10^{29} W
E:1.0×10301.0 \times 10^{30} W
F:2.0×10302.0 \times 10^{30} W
G:2.5×10332.5 \times 10^{33} W
H:1.0×10341.0 \times 10^{34} W

Practice Questions

Practice Question 1
Two variables are connected by the relation: P1Q2P \propto \frac{1}{Q^2}.

Q is increased by 40%.

To the nearest percent, describe the change in P in percentage terms.
A:29% decrease
B:44% decrease
C:49% decrease
D:51% decrease
E:80% decrease
F:96% decrease

Frequently asked questions

What is the difference between yy being proportional to xx and yy being proportional to x2x^2?

If yxy \propto x, doubling xx doubles yy. If yx2y \propto x^2, doubling xx quadruples yy (since 22=42^2 = 4). The first is a linear relationship, while the second is a quadratic relationship.

Can the constant kk be negative?

Yes, kk can be any non-zero real number. However, in most practical TMUA contexts like distance or count, kk is usually positive.

How do I interpret 'x is inversely proportional to the square root of y'?

This is written algebraically as x=kyx = \frac{k}{\sqrt{y}}. To solve, you would square terms or rearrange to isolate kk or the unknown variable.

Does a line with a negative gradient represent inverse proportion?

No. A straight line with a negative gradient is a linear relationship of the form y=mx+cy = -mx + c. Inverse proportion y=kxy = \frac{k}{x} is a curve, not a straight line.

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