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Trigonometry for the TMUA

Updated August 2025

Master the essential laws governing non-right-angled triangles. This lesson covers the sine and cosine rules, the trigonometric formula for triangle area, and the complexities of the ambiguous case. These tools allow you to solve geometric problems in both two and three dimensions.

Core concept

The sine and cosine rules relate the side lengths and interior angles of any triangle, extending Pythagoras' theorem and right-angled trigonometry to all geometric scenarios.

Trigonometry in the TMUA often requires applying relationships between sides and angles in triangles that are not right-angled. To do this, we use a standard labelling convention: corners are labelled with capital letters AA, BB, and CC, while the sides opposite them are labelled with corresponding lower-case letters aa, bb, and cc.

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The Area of a Triangle

The most fundamental formula for the area of a triangle is Area=12×base×vertical heightArea = \frac{1}{2} \times \text{base} \times \text{vertical height}, or 12bh\frac{1}{2}bh.

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This formula holds even if the top corner is not directly above the base. In such cases, one must be careful to use the vertical height above the horizontal base rather than a slanted height. This can be visualised by adding an identical triangle to form a parallelogram.

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Using trigonometry, we can calculate the vertical height if it is not provided. In the diagram below, the height hh can be expressed as bsinCb \sin C. Substituting this into the area formula gives a version that uses two sides and the included angle:

Area=12absinCArea = \frac{1}{2}ab \sin C

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The Sine Rule

The sine rule is essentially a statement that the area of a triangle is constant regardless of which base and angle you choose for the calculation. Since the area can be written as 12absinC\frac{1}{2}ab \sin C, 12bcsinA\frac{1}{2}bc \sin A, or 12casinB\frac{1}{2}ca \sin B, we can set them equal:

12absinC=12bcsinA=12casinB\frac{1}{2}ab \sin C = \frac{1}{2}bc \sin A = \frac{1}{2}ca \sin B

Multiplying by 2 and dividing by abcabc yields the standard form of the sine rule:

sinAa=sinBb=sinCc\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}

Alternatively, it can be written as asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}. You use this rule when given two angles and one side (to find another side) or two sides and one non-included angle (to find another angle).

The Ambiguous Case of the Sine Rule

When using the sine rule to find an angle given two sides and a non-included angle, an 'ambiguous' result can occur. This happens because for any value of sinθ\sin \theta, there are two possible angles between 00^{\circ} and 180180^{\circ} that satisfy it: θ\theta and 180θ180^{\circ} - \theta.

Example: In triangle ABCABC, angle A=30A = 30^{\circ}, side b=6b = 6, and side a=4a = 4. Find angle BB.

Using the sine rule: sinB6=sin304\frac{\sin B}{6} = \frac{\sin 30^{\circ}}{4} sinB=6sin304=34\sin B = \frac{6 \sin 30^{\circ}}{4} = \frac{3}{4}

Calculated values for BB are 48.648.6^{\circ} or 18048.6=131.4180^{\circ} - 48.6^{\circ} = 131.4^{\circ}. Both are plausible because 30+48.6<18030^{\circ} + 48.6^{\circ} < 180^{\circ} and 30+131.4<18030^{\circ} + 131.4^{\circ} < 180^{\circ}.

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The Cosine Rule

The cosine rule acts as a more general form of Pythagoras' theorem. In a right-angled triangle, a2=b2+c2a^2 = b^2 + c^2.

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If the angle AA is not 9090^{\circ}, we require a correction term. By considering the coordinates and projections of the sides, we derive:

a2=b2+c22bccosAa^2 = b^2 + c^2 - 2bc \cos A

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This rule is used when you are given all three sides and want to find an angle, or when you are given two sides and the angle between them to find the third side. The rearranged form for finding an angle is cosA=b2+c2a22bc\cos A = \frac{b^2 + c^2 - a^2}{2bc}.

Two and Three Dimensions

These rules are not limited to 2D triangles. In 3D problems, you should identify right-angled or non-right-angled triangles within the shape. Often, a side length calculated in one triangle (e.g., on the base of a pyramid) becomes a known side for a second triangle (e.g., a vertical cross-section).

Key takeaways

  • The area of any triangle is 12absinC\frac{1}{2}ab \sin C, where CC is the included angle.
  • Use the Sine Rule when given two angles and a side, or two sides and an angle not between them.
  • The ambiguous case occurs when the sine rule yields two possible angles that both satisfy the 180180^{\circ} sum rule.
  • Use the Cosine Rule (a2=b2+c22bccosAa^2 = b^2 + c^2 - 2bc \cos A) when given two sides and the included angle.
  • In 3D problems, look for 2D triangles embedded within the structure to apply these rules step-by-step.
Tips

In the TMUA, try to keep your answers in exact form (e.g., using sin60=32\sin 60^{\circ} = \frac{\sqrt{3}}{2}) for as long as possible. This avoids rounding errors and often leads to simplifications in multi-step 3D problems.

Cautions

A common mistake in the ambiguous case is forgetting to check if the obtuse angle is actually possible. If the sum of the given angle and the new obtuse angle exceeds 180180^{\circ}, then only the acute solution is valid.

Insight

The Sine Rule can be linked to the circumradius (RR) of the triangle. Specifically, asinA=2R\frac{a}{\sin A} = 2R. This is proven by drawing a diameter through one vertex and using the circle theorem that the angle in a semi-circle is a right angle.

Worked Examples

Example 1
The lengths of the sides QRQR, RPRP and PQPQ in triangle PQRPQR are aa, a+da + d and a+2da + 2d respectively, where aa and dd are positive and such that 3d>2a3d > 2a.
What is the full range, in degrees, of possible values for angle
PRQPRQ?
A:0<angle PRQ<600 < \text{angle } PRQ < 60
B:0<angle PRQ<1200 < \text{angle } PRQ < 120
C:60<angle PRQ<12060 < \text{angle } PRQ < 120
D:60<angle PRQ<18060 < \text{angle } PRQ < 180
E:120<angle PRQ<180120 < \text{angle } PRQ < 180

Practice Questions

Practice Question 1
A triangle ABCABC is to be drawn with AB=10cmAB = 10\text{cm}, BC=7cmBC = 7\text{cm} and the angle at AA equal to θ\theta, where θ\theta is a certain specified angle.
Of the two possible triangles that could be drawn, the larger triangle has three times
the area of the smaller one.
What is the value of
cosθ\cos \theta?
A:57\frac{5}{7}
B:151200\frac{151}{200}
C:225\frac{2\sqrt{2}}{5}
D:175\frac{\sqrt{17}}{5}
E:518\frac{\sqrt{51}}{8}
F:348\frac{\sqrt{34}}{8}

Frequently asked questions

How do I know whether to use the Sine Rule or the Cosine Rule?

Use the Cosine Rule if you have three sides (SSS) or two sides and the angle between them (SAS). Use the Sine Rule for all other cases, such as two angles and one side (AAS) or two sides and a non-included angle (SSA).

Why does the ambiguous case only happen with the Sine Rule?

The ambiguous case occurs because the sin\sin function is positive for both acute and obtuse angles. The cos\cos function, however, is positive for acute angles and negative for obtuse angles, so the Cosine Rule identifies the specific angle uniquely.

What happens to the Cosine Rule if the angle is 9090^{\circ}?

If A=90A = 90^{\circ}, then cos90=0\cos 90^{\circ} = 0. The formula a2=b2+c22bccosAa^2 = b^2 + c^2 - 2bc \cos A simplifies to a2=b2+c2a^2 = b^2 + c^2, which is Pythagoras' theorem.

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